ACT Math: Given sin θ = -5/13 in Quadrant III, Find tan θ + cos θ
In Quadrant III (pi < theta < 3pi/2), sin theta = -5/13 => cos theta = -12/13 (since cos is negative in Q3). Then tan theta = sin/cos = (-5/13)/(-12/13) = 5/12. tan theta + cos theta = 5/12 - 12/13 = (65 - 144)/156 = -79/156.
Exact Question Text
Given that $\sin\theta = -\frac{5}{13}$ and $\pi < \theta < \frac{3\pi}{2}$ (Quadrant III), what is the value of $\tan\theta + \cos\theta$?
Step-by-Step Solution
- Pythagorean Identity:
$$ \cos^2\theta = 1 - \sin^2\theta = 1 - \left(-\frac{5}{13}\right)^2 = 1 - \frac{25}{169} = \frac{144}{169} $$ In Quadrant III, cosine is negative $\implies \cos\theta = -\frac{12}{13}$.
- Compute $\tan\theta$:
$$ \tan\theta = \frac{\sin\theta}{\cos\theta} = \frac{-5/13}{-12/13} = +\frac{5}{12} $$
- Evaluate the Expression:
$$ \tan\theta + \cos\theta = \frac{5}{12} + \left(-\frac{12}{13}\right) = \frac{65 - 144}{156} = -\mathbf{\frac{79}{156}} $$
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