ACT Science: 3-Variable Graph Interpretation (Temperature, Salinity & Dissolved Oxygen)
To read 3-variable plots on ACT Science, hold one variable constant on the horizontal axis (e.g. 20°C), trace vertically to the specific series curves in the legend (0 ppt vs 35 ppt), and read the dissolved oxygen value on the vertical axis: delta = 7.3 - 9.1 = -1.8 mg/L.
Exact Question Scenario
A limnology research team investigates how water temperature ($^\circ\text{C}$) and salinity ($\text{ppt}$) influence equilibrium dissolved oxygen ($\text{DO}$, in $\text{mg/L}$).
- X-axis: Water Temperature ($0^\circ\text{C}$ to $30^\circ\text{C}$)
- Y-axis: Dissolved Oxygen ($\text{mg/L}$)
- Series: $0\text{ ppt}$ (Solid line), $15\text{ ppt}$ (Dashed line), $35\text{ ppt}$ (Dotted line)
Question: According to Figure 1, at a constant water temperature of $20^\circ\text{C}$, if the salinity increases from $0\text{ ppt}$ to $35\text{ ppt}$, the dissolved oxygen concentration will:
- A) Increase by approximately $3.2\text{ mg/L}$
- B) Decrease by approximately $1.8\text{ mg/L}$
- C) Decrease by approximately $5.4\text{ mg/L}$
- D) Remain unchanged at $9.1\text{ mg/L}$
Step-by-Step Solution
- Find $20^\circ\text{C}$ on horizontal axis.
- Read $0\text{ ppt}$ curve: $\text{DO} \approx 9.1\text{ mg/L}$.
- Read $35\text{ ppt}$ curve: $\text{DO} \approx 7.3\text{ mg/L}$.
- Delta: $7.3 - 9.1 = -1.8\text{ mg/L}$.
- Correct Answer: B
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Never read the passage text first. Go directly to the question stem, find the Figure number, and read the axes and line markers directly.
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