Digital SAT Math
SAT Math: If 9x² - 64 = (ax + b)(ax - b), What Is the Value of a + b?
• Direct Answer / Key Takeaway
(3x + 8)(3x - 8) => a = 3, b = 8. Thus a + b = 3 + 8 = 11.
Exact Question Text
If 9x^2 - 64 = (ax + b)(ax - b) for all values of x, where a and b are positive constants, what is the value of a + b?
1. Step-by-Step Formal Solution
- Difference of squares: (3x)^2 - (8)^2 = (3x + 8)(3x - 8).
- a = 3, b = 8 => a + b = 11.
2. Fast Desmos / Calculator Shortcut
Evaluate sqrt(9) + sqrt(64) = 3 + 8 = 11.
3. Distractor Trap Analysis
- Trap A (Sign Flip): Forgetting to reverse inequality or dropping negative sign.
- Trap B (Partial Evaluation): Solving for intermediate variable and stopping early.
- Trap C (Extreme Assumption): Over-inferring beyond textual evidence.
- Option Correct: Accurately satisfies all algebraic and logical constraints.
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