SAT Math: In Right Triangle ABC, Altitude CD is Drawn to Hypotenuse AB (AD=4, DB=16)
By the Geometric Mean Altitude Theorem, the altitude to the hypotenuse is the geometric mean of the two hypotenuse segments: (CD)^2 = AD * DB. Given AD = 4 and DB = 16, (CD)^2 = 4 * 16 = 64 => CD = 8.
Exact Question Text
In right triangle $\triangle ABC$, angle $C$ is a right angle. Altitude $\overline{CD}$ is drawn to the hypotenuse $\overline{AB}$.
If $AD = 4$ and $DB = 16$, what is the length of $\overline{CD}$?
Step-by-Step Solution
- Apply Geometric Mean (Altitude) Theorem:
Drawing altitude $CD$ creates two similar sub-triangles $\triangle ADC \sim \triangle CDB$:
$$ \frac{AD}{CD} = \frac{CD}{DB} \implies (CD)^2 = AD \cdot DB $$
- Substitute Values:
$$ (CD)^2 = 4 \cdot 16 = 64 \implies CD = \sqrt{64} = \mathbf{8} $$
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What is the Geometric Mean Theorem on SAT right triangles?
Altitude^2 = segment1 * segment2. Leg^2 = adjacent segment * total hypotenuse.
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