SAT Math: Circle (x - 3)² + (y + 2)² = 25 Tangent to Line L at (6, 2), Find Slope
Center is (3, -2). Radius slope m_rad = (2 - (-2))/(6 - 3) = 4/3. Tangent slope m_tan = -3/4.
Exact Question Text
In the xy-plane, the circle (x - 3)^2 + (y + 2)^2 = 25 is tangent to line L at (6, 2). What is the slope of line L?
1. Step-by-Step Formal Solution
- Center = (3, -2), Point = (6, 2).
- m_radius = (2 - (-2)) / (6 - 3) = 4/3.
- Perpendicular slope m_tangent = -1 / (4/3) = -3/4.
2. Fast Desmos / Calculator Shortcut
Plot circle and point (6, 2). Calculate -(6-3)/(2 - (-2)) = -3/4.
3. Distractor Trap Analysis
- Trap A (Sign Flip): Forgetting to reverse inequality or dropping negative sign.
- Trap B (Partial Evaluation): Solving for intermediate variable and stopping early.
- Trap C (Extreme Assumption): Over-inferring beyond textual evidence.
- Option Correct: Accurately satisfies all algebraic and logical constraints.
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